invariant-guard – skill Viết lách & Nội dung cho agent AI

invariant-guard — Correctness-First Coding

The model knows what a loop invariant is. It knows recursion needs a base case. It knows about empty lists, integer overflow, and the difference between < and ≤. It just does not write these down before producing code, so it ships subtle correctness bugs that tests do not catch.

invariant-guard fixes the behavior. State the invariants. State the base case. State the termination argument. State the edge cases. Then write the code — and verify that the code maintains what you stated.

Violating the letter of these rules is violating the spirit of the skill. "I know this algorithm" is the exact rationalization that ships off-by-one and missing-postcondition bugs.

When to Use This Skill

Use invariant-guard when writing or reviewing algorithms where the obvious implementation is subtly wrong:

• Postcondition stronger than the loop's natural invariant: Boyer–Moore majority, Floyd's cycle detection, leftmost vs any binary search, QuickSelect partition.
• In-place mutation with read+write pointers: dedup-in-place, partition, rotate.
• Recursion with multiple parameters or accumulator state.
• Off-by-one suspects with duplicates, empty inputs, boundary values.
• Iterative refinements that must terminate: fixed-point, Newton, EM.
• Any function where you catch yourself thinking "I know this algorithm" — the trap is usually in the contract, not the loop body.

Pairs with lemmaly (picks the algorithm) and mathguard (picks the math). Load invariant-guard *after* the algorithm has been chosen and *before* the loop body is written.

The Iron Law

NO LOOP OR RECURSION WITHOUT A WRITTEN INVARIANT AND TERMINATION ARGUMENT

If you cannot write the invariant in one sentence, you have not designed the loop. Write code anyway and you are coding by guess — and the bug will be in the case you did not enumerate.

Non-negotiable rules

1. Every loop gets a one-line invariant. Before writing any loop, state in one sentence what is true at the top of every iteration. Examples:

• "At loop top: result contains the sum of a[0..i)."
• "At loop top: lo ≤ target_position ≤ hi."
• "At loop top: seen contains every element processed so far; dups contains every element that appeared at least twice."

If you cannot write the invariant in one sentence, you have not designed the loop yet.

2. Every loop gets a one-line termination argument. Name the quantity that strictly decreases (or strictly increases toward a bound) on every iteration. Examples:

• "hi − lo strictly decreases each iteration."
• "i increases by 1 and is bounded above by n."
• "stack.length strictly decreases each pop; nothing pushes inside this branch."

No termination argument, no loop.

3. Every recursion gets an explicit base case and a measure. Before writing a recursive function, state:

• The base case(s) — the smallest inputs that return without recursing.
• The measure — a non-negative integer that strictly decreases on every recursive call (e.g. len(xs), hi − lo, depth, n).
• The combination — how the recursive results combine into the answer.

No base case + measure, no recursion. (Mutual recursion: state the measure across the cycle.)

4. List edge cases before writing, not after. For every function operating on a collection or number, list which of these apply and how they behave:

• Empty input ([], "", null, undefined, None).
• Singleton ([x]).
• All-equal elements.
• Already-sorted / reverse-sorted input.
• Duplicates (when uniqueness is assumed).
• Negative numbers, zero, exactly the boundary value.
• Integer overflow / underflow at the type max/min.
• NaN, ±Infinity, -0, denormals (for floats).
• Off-by-one boundaries: index 0, index n−1, index n, length 0, length 1.
• Concurrent modification while iterating.

The cases that apply must each have a one-phrase expected behavior written down.

5. Make illegal states unreachable, not just unhandled. Prefer encoding constraints in types and structure so the wrong state cannot be constructed:

• Sum type over boolean flag soup (Loading | Loaded(data) | Error(msg) not {loading, data, error}).
• Newtype for IDs that must not be swapped (UserId vs OrderId).
• Non-empty list type when the function requires at least one element.
• Parsed value at the boundary, not validated repeatedly downstream (parse-don't-validate).

If the language cannot encode it, write the invariant as a comment and assert it at the boundary.

The pre-write protocol

Before producing non-trivial code that has loops, recursion, or non-trivial state, your message must contain — in this order:

1. Function contract — preconditions, postconditions, and what the function returns. One line each.

2. Loop invariants — one per loop. (Rule 1.)

3. Termination arguments — one per loop or recursion. (Rules 2, 3.)

4. Base cases and measure — for recursion. (Rule 3.)

5. Edge case table — bullets, one per applicable case, with expected behavior. (Rule 4.)

6. Illegal states made unrepresentable — name the types or asserts that enforce invariants. (Rule 5.)

7. The code.

8. Self-check — one line per loop confirming the invariant holds at top, body preserves it, and exit implies postcondition.

If any of 1–6 is missing, do not emit code.

Worked trap — Boyer–Moore majority vote

This is the canonical "the trap is in the contract, not the loop body" case.

Naive baseline (what gets shipped without the skill):

function findMajority(arr: number[]): number | null {
  if (arr.length === 0) return null;
  let candidate = arr[0], count = 0;
  for (const x of arr) {
    if (count === 0) candidate = x;
    if (x === candidate) count++; else count--;
  }
  return candidate;   // BUG: returns the candidate even when no majority exists
}

This implementation fails on [1,2,3] (returns 3, expected null) and [2,2,1,1] (returns 2, expected null). The voting loop is correct; the postcondition is wrong.

Why the protocol catches it. Writing step 1 (function contract) forces the postcondition in plain language:

> Returns x iff count(x, arr) > arr.length / 2; else null.

Then writing step 2 (loop invariant) forces the invariant of the voting pass:

> The processed prefix can be partitioned into pairs of unequal values plus count copies of candidate. This cancellation invariant implies the final candidate is the majority if a strict majority exists.

These two statements are not equivalent. The loop invariant guarantees "if a majority exists, it is the candidate" — not "the candidate is a majority." Once you write both down, the gap is visible: you need a second pass to verify, or the postcondition is unmet.

Correct implementation that survives the protocol:

function findMajority(arr: number[]): number | null {
  if (arr.length === 0) return null;
  // Pass 1: vote.
  let candidate = arr[0], count = 0;
  // inv: processed prefix = unequal canceled pairs plus count copies of candidate.
  // term: the finite array iterator advances once per iteration.
  for (const x of arr) {
    if (count === 0) candidate = x;
    if (x === candidate) count++; else count--;
  }
  // Pass 2: verify — the voting invariant is strictly weaker than the postcondition.
  let tally = 0;
  // inv: tally = count of candidate in arr[0..i).
  for (const x of arr) if (x === candidate) tally++;
  return tally * 2 > arr.length ? candidate : null;
}

Pattern to generalize. The same trap appears in:

• Floyd's cycle detection — finding the meeting point tells you a cycle exists, *not* where it starts. You need a second walk.
• Two-pointer "find any" vs "find leftmost" — the loop invariant for one does not satisfy the postcondition of the other.
• QuickSelect partition — the loop returns a position; the postcondition is that the element at that position is the k-th smallest. Off by one in the partition invariant silently breaks it.
• DP with reconstruction — the table tells you the optimum value; reconstructing the optimum path needs separate invariants on the choice array.

In every case: write the postcondition first; write the loop invariant second; check that the second implies the first. If not, you are missing a pass, a check, or an auxiliary state.

Canonical example — binary search for the leftmost match

Most "I know binary search" implementations are written for "find any match." The trap is the postcondition.

Problem. Given a sorted array with duplicates, return the index of the leftmost occurrence of target, or -1.

Without the protocol — returns any match

function leftmost(a: number[], target: number): number {
  let lo = 0, hi = a.length - 1;
  while (lo <= hi) {
    const mid = lo + Math.floor((hi - lo) / 2);
    if (a[mid] =

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